Determine the AP whose 3rd term is 5 and the 7th term is 9.
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a+2d=5.... (1)
a+6d=9.......(2)
equating (1) and (2)
d=1
put value of d in (1) we get
a= 3
Ap.= 3,4,5,6......
a+6d=9.......(2)
equating (1) and (2)
d=1
put value of d in (1) we get
a= 3
Ap.= 3,4,5,6......
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