determine the ap whose 3rd term is 5 and the 7th term is 9.
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a3 = 5
a7 = 9
a3 = 5
a+2d = 5 — 1
a7 = 9
a + 6d = 9 —2
using elimination method
a+2d = 5
a + 6d = 9
- - -
———————
- 4d = - 4
d = 1
d put in 1
a + 2(1) = 5
a + 2 = 5
a = 5-2
a = 3
a = 3
a2 = a+d = 3+1 = 4
a3 = a + 2d = 3 + 2(1) = 5
A.P = 3,4,5
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