determine the ap whose 3rd term is 8 and the 7th term is 12
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Step-by-step explanation:
=> a3 = 8 and a7 = 12
=> a3 = a + ( 3-1 ) d. a7 = a + ( 7-1 ) d
=> 8 = a + 2d --- 1 12 = a + 6d ---- 2
=> from 1 and 2
=> 4d = 4. => d = 1
=> from 1
a + 2 (1) = 8
a + 2 = 8
a = 8 - 2 = 6
=> a1 = a = 6
a2 = a + d = 6 + 1 = 7
a3 = a + 2d = 6 + 1*2 = 6 + 2 = 8
A.P = 6, 7, 8, 9
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