Math, asked by rakesh25jnv, 7 months ago

determine the AP whose 3rd terms 16and 7th term exceeds the 5th term by12​

Answers

Answered by Anonymous
1

Answer:

Hope it helps uh...be happy

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Answered by coolyadav111111
0

Answer:

3rd term 16

7th term = 5th+ 12

a +(3-1)d= a+2d = 16 1st equ.

a+6d = a+4d+ 12 2nd equ.

from 2nd

2d = 12

d = 6

putting the value of d in 1st equ.

a+ 2×6 = 16

a = 4

therefore, ap is 4,10,16,22,28,34......

hope it is help u

pls make me brain..

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