determine the ap whose 4th term is 18 and the difference is 9th term from 15th terms 36
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Answered by
1
Answer:
a4 = 18
a+3d=18...
a15-a9=36
a+14d-(a+8d) = 36
a+14d-a-8d = 36
6d = 36
d= 6
a+18 =18
a= 18-18
a=0
the terms of Ap are 0,6,12,18 ......
Answered by
0
Answer:a4 = 18a+3d=18...a15-a9=36a+14d-(a+8d) = 36a+14d-a-8d = 366d = 36 d= 6a+18 =18a= 18-18a=0the terms of Ap are 0,6,12,18 ......
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