Determine the ap whose fifth term is 15 and the sum of its 3rd and 8th term is 34
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Here is the answer, hope it helps.
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Step-by-step explanation:
t5 = 15
a+ 4d = 15........(1)
t3 + t8 = 34
a+ 2d + a + 7d = 34
2a + 9d = 34.......(2)
multiply (1) by 2 ---> 2a + 8d = 30.....(3)
Now let's solve (3) &(2)
2a + 9d = 34
2a + 8d = 30
_____________
d = 4
substitute d = 4 in (3)
2a + 32 = 30
a = -1
t1 = -1
t2 = 3
t3 = 7
So, your A.P is -1,3,7
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