Determine the ap whose fourth term is 18 and the difference of the 9th term from the 15th term is 30
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a+3d=18 and a+14d-a-8d=30
6d=30 therefore d =5
now a+3x5=18
a+15=18
a=18-15= 3
AP is 3, 8,13, .....
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