determine the ap whose term3 is 5 & term7 is 9
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The ap is 3,4,5.......
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AP
tn = a + (n - 1 )d
t3 = 5 = a + ( 3 - 1 ) d
5= a + 2d .........................1
t7 = 9 = a + 6d
9 = a + 6d .......................2
subtract 1 from 2
a + 6 d= 9
a + 2d = 5 subtract
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4d = 4
d = 1
a + 2d = 5
a = 5 - 2d
= 5 - 2
= 3
therefore the AP is 3 , 4 , 5 .....................( answer )
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