determine the ap whose third is 16 and the 7th term exceeds 5th term by 12
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third term = 16
therefore , a + 2d = 16
now,
. a + 6d = a + 4d + 12
. 2d = 12
. d = 6
therefore
=> a + 2d = 16
=> a + 12 = 16
=> a = 4
so the ap is 4, 10, 16, 22, 28 ,.....
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