determine the ap whose third term is 16 and 17th term exceeds the 5th term by 12
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T3=16
a+2d=16......(1)
T17=T5+12
a+16d=a+4d+12
16d-4d=12
12d=12
d=1
putting the value of d in equation 1 weget
a+2×1=16
a=16-2
a=14
the following AP are
a,(a+d),(a+2d),(a+3d)....
14,15,16,17....
a+2d=16......(1)
T17=T5+12
a+16d=a+4d+12
16d-4d=12
12d=12
d=1
putting the value of d in equation 1 weget
a+2×1=16
a=16-2
a=14
the following AP are
a,(a+d),(a+2d),(a+3d)....
14,15,16,17....
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