determine the AP whose third term is 16 and 17th term exceeds the 5th term by 12
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Answered by
7
a+ 2d =16
a + 16d - a -4d = 12
12d = 12
d = 1
a = 14
then AP == 14 , 15 , 16, 17 ........
a + 16d - a -4d = 12
12d = 12
d = 1
a = 14
then AP == 14 , 15 , 16, 17 ........
Answered by
5
Hyyyy mate....
thanks for the question...
Ur ans is here in the attachment....
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Hope it helps u
thanks for the question...
Ur ans is here in the attachment....
.
.
.
Hope it helps u
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