Question

determine the AP whose third term is 16 and 7th term exceeds the 5th term by 12

Answer 1

HEYA!!!!

Here is your answer :
___________________________

Given,

7th term exceeds 5th term by 12

a + 6d = a + 4d + 12

6d - 4d = 12

2d = 12

d = 6,,


From,

3rd term = 16

a + 2d = 16

a + 2 (6) = 16

a + 12 = 16

a = 4

Therefore,

AP = 4 , 10 , 16.........




HOPE THIS HELPS U. . .

Answer 2

Answer

a3 = 16

=> a + 2d = 16

=> a = 16 - 2d

a7 = a5 + 12

=> a + 6d = a + 4d + 12

=> 2d= 12

=> d = 6

a = 16 - 2d

=> a = 16 - 12

=> a = 4

AP = 4, 10, 16...