determine the ap whose third term is 16 and 7th term exceeds the 5th term by 12
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sofiyasofii24:
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★Assume the a be first term
★d be the common difference
= 12
★Here we have :-
a + 2d = 16 ..... (1)
★Also we have :-
(a + 6d) - (a + 4d) = 12
a + 6d - a - 4d = 12
2d = 12
d = 6 ..... (2)
a + 2(6) = 16
a + 12 = 16
a = 16 - 12
a = 4
★Hence AP are :-
(4)
(4 + 6) = 10
(4 + 2 × 6) = 4 + 12 = 16
(4 + 3 × 6) = 4 + 18 = 22
★AP are :-
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