Math, asked by sofiyasofii24, 1 year ago

determine the ap whose third term is 16 and 7th term exceeds the 5th term by 12​

Answers

Answered by ashutosh1123
8

Answer

mark brainliest if it helps..

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sofiyasofii24: not much clear
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sofiyasofii24: any way thanks..
ashutosh1123: Is it correct
sofiyasofii24: yes
ashutosh1123: Mrk brainliest
sofiyasofii24: how??
sofiyasofii24: ????
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Answered by Anonymous
21

\textbf{\underline{\underline{According\:to\:the\:Question}}}

{\boxed{\sf\;{Arithemetic\;Progression}}}

★Assume the a be first term

★d be the common difference

\rightarrow{a_{3}=16}

\rightarrow{a_{7}-a_{5}}

= 12

★Here we have :-

a + 2d = 16 ..... (1)

★Also we have :-

(a + 6d) - (a + 4d) = 12

a + 6d - a - 4d = 12

2d = 12

{\boxed{\sf\:{d=\dfrac{13}{2}}}}

d = 6 ..... (2)

\fbox{Substitute\;the\;value\;of\;(2) in (1) :-}

a + 2(6) = 16

a + 12 = 16

a = 16 - 12

a = 4

★Hence AP are :-

(4)

(4 + 6) = 10

(4 + 2 × 6) = 4 + 12 = 16

(4 + 3 × 6) = 4 + 18 = 22

★AP are :-

\fbox{4 , 10 , 16 , 22}

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