Question

determine the AP whose third term is 16 and 7th term is more than 5th term by 12​. Please answer fast. Answer as soon as possible

Answer 1

★ Formulas used : a+(n-1)d

★ Solution :

a3 = a+(3-1)×d = 16

a3 = a+2d

a3+2d = 16

a+12= 16

a = 16-12

$\boxed{→ a3 = 4}$

a7 = a+(7-1)×d

a7 = a+6d

Here, we got a=4 and d=6.

a5 = a+(5-1)×d

a5 = a+4d

a+6d = a+4d+12

6d = 4d = 12

6d-4d = 12

2d = 12

$d = \frac {12}{2}$

$\boxed{→ d=6}$

•°• Ap formed will be 4,10,16,22 ......

Answer 2

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