Determine the ap whose third term is 16 and seventh term exceeds fifth term by 12
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3
a + 2d = 16
(a + 6d) - (a + 4d) = 12
a + 6d - a - 4d = 12
2d = 12
d = 6
a + 2d = 16
a + 2(6)
a + 12 = 16
a = 16 - 12 = 4
A.P = a , a + d , a + 2d, a + 3d ....
A.P = 4 , 10 , 16 , 22 , 28 , 34 .......
Answered by
4
Answer
a3 = 16
=> a + 2d = 16
=> a = 16 - 2d
a7 = a5 + 12
=> a + 6d = a + 4d + 12
=> 2d= 12
=> d = 6
a = 16 - 2d
=> a = 16 - 12
=> a = 4
AP = 4, 10, 16...
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