Question

Determine the ap whose third term is 16 and seventh term exceeds fifth term by 12

Answer 1

a + 2d = 16

(a + 6d) - (a + 4d) = 12

a + 6d - a - 4d = 12

2d = 12

d = 6

a + 2d = 16

a + 2(6)

a + 12 = 16

a = 16 - 12 = 4

A.P = a , a + d , a + 2d, a + 3d ....

A.P = 4 , 10 , 16 , 22 , 28 , 34 .......

Answer 2

Answer

a3 = 16

=> a + 2d = 16

=> a = 16 - 2d

a7 = a5 + 12

=> a + 6d = a + 4d + 12

=> 2d= 12

=> d = 6

a = 16 - 2d

=> a = 16 - 12

=> a = 4

AP = 4, 10, 16...