Determine the AP whose third term is 16 and the 7th term exceed
5th term by 12
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Answered by
18
given,
a(3 rd term)=6
a+2d=6 -(1)
a(7 th term) - a(5th term)=12
a+6d-a-4d=12
2d=12
d=6
put d =6 in (1)
a+12=16
a=4
So, A.P is : 4,10,16.....
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15
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