Math, asked by dhananjay8833, 1 year ago

Determine the AP whose third term is 16 and the 7th term exceeds the 5th ten by 12?

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Answered by adityaaryaas
1

Answer:

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Answered by Anonymous
4

Answer

a3 = 16

=> a + 2d = 16

=> a = 16 - 2d

a7 = a5 + 12

=> a + 6d = a + 4d + 12

=> 2d= 12

=> d = 6

a = 16 - 2d

=> a = 16 - 12

=> a = 4

AP = 4, 10, 16...

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