determine the AP whose third term is 5 and 7th term is 9
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Given.
A3=5
A7=9
But
A3=a+2d
→5=a+2d →(1)
and
A7=a+6d
→9=a+6d →(2)
Substracting (1) from (2)
9=a+6d -
5=a+2d
---------------
→4=4d
→d=4/4=1 →(3)
Substituting (3) in (1)
→5=a +2×1
→a+2=5
→a=5-2=3
So the AP is 3,4,5,6,7,8,9,10,....,n
Hope you understand,
Regards,
Leukonov.
A3=5
A7=9
But
A3=a+2d
→5=a+2d →(1)
and
A7=a+6d
→9=a+6d →(2)
Substracting (1) from (2)
9=a+6d -
5=a+2d
---------------
→4=4d
→d=4/4=1 →(3)
Substituting (3) in (1)
→5=a +2×1
→a+2=5
→a=5-2=3
So the AP is 3,4,5,6,7,8,9,10,....,n
Hope you understand,
Regards,
Leukonov.
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