Determine the AP whose third term is 5 and the seventh term is 9
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Here,
Given,
3rd term = 5
Also,
7th term = 9
Situation,
a5 = 5
a + 4d = 5 .......... (1)
Also,
a7 = 9
a + 6d = 9 ............ (2)
Now,
Subtract (1) from (2) we get,
a + 6d - a + 4d = 9 - 5
a + 6d - a + 4d = 4
2d = 4
d = 4/2
d = 2
Now,
Substitute the value of d in (1) :-
a + 4d = 5
a + 4 × 2 = 5
a + 8 = 5
a = 5 - 8
a = -3
Hence,
Arithmetic Progression are -3, -1 , 1.........
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