Question

Determine the AP whose third term
whose third term is 16 and the 7th term exceeds the 5th term by 12​

Answer 1

Answer:

4,10,16,22....

Step-by-step explanation:

a3=16

a7=a5+12

a+6d=a+4d+12

2d=12

d=6

a+2d=16

a+12=16

a=4

Answer 2

Answer:

hey dude ans.. is here

Step-by-step explanation:

Let a be the First term, a3 be the third term, a5 be the 5th term and a7 be the 7th term

a3 = 16

a7 = a5 + 12 ............ (1)

Let the common difference be "d"

Common difference is equal in AP

So,

a7 = a5 + d + d = a5 + 2d ............(2)

From Equation (1) & (2)

a5 + 12 = a5 + 2d

2d = 12

d = 6

From Given, we get that

a3 = 16

a3 = a + 2d = 16

a + ( 2 × 6 ) = 16 [ We know that d = 6 ]

a + 12 = 16

a = 4

So first term is 4 .... We can find AP by adding d continuously

So, AP is 4, 10, 16, 22, 28....

hope it is useful dear..