Question

determine the area of rectangle whose length is 16cm and perimeter Is 48cm

Answer 1

perimeter of rectangle=2(l+b)
$48 = 2(16 + b) \\ \frac{48}{2} = 16 + b \\ 24 = 16 + b \\ 24 - 16 = b \\ 8 cm= b$

breadth= 8 cm
area of rectangle =l×b
$= 16 \times 8 \\ = 128 cm sq$
hope it helps

Answer 2

hlo mate.

here is your answer.

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Firstly,
let's find the breadth.

perimeter of rectangle =2 (l+b)
= > 2(16 + b) = 48
48 ÷ 2 = 16 + b
24 =16+b
b=24-16
b=8.

hence, area of rectangle =length ×breadth.
=16cm×8cm
=128 cm.sq

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hope it helps you
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