Question

Determine the area of the rectangular ABCD with AB=5cm and BC =3cm

Answer 1

area- AB×BC
=5×3
=15

Answer 2

The area of the rectangle ABCD is $15\;cm^{2}$.

• A rectangle is a regular shape that consists of four sides out of which the sides which are greater in magnitude is called the length and the relatively shorter sides are known as the breadth of the rectangle.
• The lengths of the rectangle are said to be equal and opposite to each other. The lengths and the breadths are at right angles to each other.
• Since the lengths of a rectangle are equal and so are its corresponding breadths, the value of one of its lengths and one of its breadths is more than sufficient to calculate the area of the rectangle.
• By definition the area of the rectangle indicates the region inside the rectangle or in other words the space enclosed within the boundary of the rectangle which is what we are asked to calculate.
• The unit of measurement of area is square units. Here, the unit given is cm so the unit of area will be in terms of $cm^2$.

The formula for the area of a rectangle in terms of its length and the breadth which must be applied to find the area. Hence, the formula is given as:

$Area=l\times b$ ----------(1)

where,

l is the length of the rectangle

b is the breadth of the rectangle

Here, there is a rectangle ABCD with its length and its breadth given.

Taking length as side AB=5 cm and breadth as side BC= 3cm since the longer side is AB.

So we have:

$l=5\;cm\\b=3\;cm$

Applying the formula given in equation (1) we have:

$Area=5\times3$

$\implies Area=15\;cm^2$

Therefore the area of the rectangle ABCD is $15\;cm^2$.

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