determine the area of the triangle whose sides are5cm, 13cm , 12 cm
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2
As we can observe that (5,13,12) are pythagorean triplets,
So,
××××××××××××
Area of right angled triangle =>
××××××××××××××
Here,
Area = 1/2 × 5 × 12
Area = 5 × 6
Area = 30 cm²
I hope this will help you
(-:
So,
××××××××××××
Area of right angled triangle =>
××××××××××××××
Here,
Area = 1/2 × 5 × 12
Area = 5 × 6
Area = 30 cm²
I hope this will help you
(-:
Answered by
2
a = 5 cm
b = 12 cm
c = 13 cm
S = ( a + b +c) / 2
=> S = (5+12+ 13)/2
=> S = ( 30 /2)
=> S = 15
Area = sqrt [ S ( s-a) (s - b) (s-c)]
= sqrt [ 15(15-5)(15-12)(15-13)]
= sqrt ( 15 × 10 × 3 × 2)
= sqrt ( 900)
= 30 cm^2
b = 12 cm
c = 13 cm
S = ( a + b +c) / 2
=> S = (5+12+ 13)/2
=> S = ( 30 /2)
=> S = 15
Area = sqrt [ S ( s-a) (s - b) (s-c)]
= sqrt [ 15(15-5)(15-12)(15-13)]
= sqrt ( 15 × 10 × 3 × 2)
= sqrt ( 900)
= 30 cm^2
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