Determine the axial force of all the forces of the loaded
truss
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For Equilibrium ∑H = 0; RAH = 15KN ∑V = 0; RAV + RBV = 0 ∑MB = 0; RAV X 4 + 10 X 4 + 5 X 8 = 0 RAV = – 20 KN And RBV = 20KN Consider Joint A as shown in fig(a) Consider Joint B as shown in fig (b) ∑H = 0; – TAB – TBF cos 45 = 0 TBF = – 15/cos 45 = – 21.21KN TBF = – 21.21KN(C) ∑V = 0 TBC + TBF sin 45 + 20 = 0 TBC – 21.21 sin 45 + 20 = 0 TBC = – 5KN(CRead more on Sarthaks.com - https://www.sarthaks.com/512383/find-out-the-axial-forces-in-all-the-members-of-a-truss-with-loading-as-shown-in-fig
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