Question

Determine the correct option for density of methane in g/L at NTP
A. 0.0071
B. 0.071
C. 0.71
D. None of the above​

Answer 1

Answer:

Option C is the right answer

Explanation:

We know that

Molecular Weight of Methane or CH4

= 12 + 4 = 16

We have to find

The density of Methane in g/L.

Well we can find it by various method and the answer will be almost same.

Method No. 1

$\boxed{Molecular \: Weight = Vapour \: Density \times 2}$

$= > 16 = 2 \times Vapour \: Density \\ = > Vapour \: Density = \frac{ \cancel{16}}{ \cancel{2}} \\ = > Vapour \: Density = 8$

$\boxed{Vapour \: Density = (\frac{density \: of \: gas}{density \: of \: H2})at \: same \: P \: and \: T}$

$= > 8 = \frac{Density \: of \: gas }{9 \times {10}^{ - 2} } \\ = > Density \: of \: gas = 9 \times 8 \times {10}^{ - 2} \\ = > Density \: of \: gas = 72 \times {10}^{ - 2} \\ = > Density \: of \: gas = \frac{72}{100} \\ = > \boxed{Density \: of \: gas = 0.72g/L}$

Method No. 2

$\boxed{Molecular \: Weight = Density \times 22.4} \\ = > 16 = Density \: of \: Gas \times 22.4 \\ = > Density \: of \: Gas = \frac{16}{22.4} \\ = > Density \: of \: Gas = \frac{ \cancel{160}}{ \cancel{224}} \\ = > Density \: of \: Gas = \frac{ \cancel{40}}{ \cancel{56}} \\ = > Density \: of \: Gas = \frac{5}{7} \\ = > \boxed{Density \: of \: Gas = 0.71g/L}$

Answer 2

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First You Should Know:-

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The Ideal Gas Equation,

PV=nRT

The Transformation Of This Equation In Order To Calculate The Density Is

PM=dRT

where

✔P is atmospheric pressure

✔M is molecular mass

✔d is density

✔R is the gas constant

and

✔T is temperature

Answer To Question

As

PM=dRT

(1)(16)=d(0.0821)(300)

So

$d = \frac{1 \times 16}{0.0821 \times 300} \\ d = \frac{16}{24.63} \\ d = 0.064$

But This is density in kg/m^3

And

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This density is 0.71 in g/L

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So (C) option is correct one

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