Question

Determine the current flowing through a pure inductor of 150 mH
when the frequency is a)50 Hz b) 60 Hz.The voltage applied is 230 V.​

Answer 1

Answer:

In a pure inductor current lags behind emf by

π/2radian or 90°...

cos∅=Resistance/impedance

Cos 90°=R/Z

so,XL=wL

but,w=2πf

XL=2πf(150mH)

a) if frequency is 50HZ

XL=2π×50×150mH

XL=15πΩ

b) if frequency is 60Hz

XL=2π×60×150mH

XL=18πΩ

Explanation:

Hope it helps you frnd.....