Question

Determine the current I flowing through the inductor
1 uF
I mH
1
31
(a) I = 2 mA
(b) 1 - 1 mA
(c) 13 mA
(d) I Oma​

Answer 1

Answer:

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Answer 2

Answer:

At V

B

=8V

i

L

=

4

6×10

−3

=1.5×10

−3

A

i

R

=

1

8−6×10

−3

=2×10

−3

A

∴i

zenerdiode

=i

R

−i

load

=0.5×10

−3

A

At V

B

=16V

i

L

=1.5×10

−3

A

i

R

=

1

(16−6)×10

−3

=10×10

−3

A

∴i

zenerdiode

=i

R

−i

L

=8.5×10

−3

A

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