determine the current IL in the circuit
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- 0.006 A = V 6000 Ω + 3 I x + 0.003 A + I x + I L 0.006A=\frac{V}{6000\Omega}+3I_x+0.003A+I_x+I_L 0.
- V 6000 Ω + 4 I x + I L = 0.003 A \frac{V}{6000\Omega}+4I_x+I_L=0.003A 6000ΩV+4Ix+IL=0.
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Explanation:
We can figure out ILby writing Kirchhoff’s current law (KCL) for the whole circuit loop. When doing this question, it’s important to remember the following equation, V=IR, where V is voltage, I is current and R is resistance. Thus, isolating for current, I, lets us represent it V/R
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