Question

Determine the current through the 5 ohm resistor in the circuit by thevenins theorem

Answer 1

Answer:

Heya mate.....

As we know that V = IR

So, V = 220 V and R = 5ohm

Now, V = IR

220 = I × 5

I = 220/5

I = 44 A

Hope it helps.....

Answer 2

The current through the 5ohm resistor in the circuit by thevenins theorem is 0.3076A

Explanation:

Given,

resistors parallel are 2Ω, 1Ω, 4Ω

$R_{e} = 0.571$Ω.

Find,

current through 5ohm resistor.

Concept used

Remove 5ohm and apply node analysis at $V_{1}$.

$\frac{20-V_{1} }{2} = \frac{V_{1} +10 }{1 } + \frac{V_{1} +12 }{4 }\\\\7V_{1} = 12\\ \\V_{1} = 1.714V$

$V_{5} = [\frac{1.714}{5+0.571}]5 = 1.538V$

Since V=1.538V

R=5

V=IR

1.538 = I(5)

I = 0.3076A

Therefore, the current through the 5ohm resistor in the circuit by thevenins theorem is 0.3076A