Determine the de broglie wavelength associated with the electron orbiting in ground state of hdrogen atom
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3
For electron in first excited state i.e. n = 2.
So, if λ be its wavelength (De-Broglie), then we have
n λ = 2πrn
where,rn is the radius of second orbit.
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2
➡Wave length
λ=hmv
=6.63×10−341.67×10−27×103
=0.4nm
λ=hmv
=6.63×10−341.67×10−27×103
=0.4nm
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