Question

Determine the Debye's temperature of a metal whose molar heat capacity at 25 K is 31.06 J mol−1K −1 ​

Answer 1

Solution:- (C) 1.0kJ

Mass of Al=54g

Molar mass of Al=27g/mol

∴ No. of moles (n)=

27

54

=2 mole

ΔT=50−30=20

Molar heat capacity (C)=25J/mol−K

∴ Total heat required =nCΔT

⇒ Total heat required =2×25×20=1000J/mol−K=1kJ/mol−K

The heat necessary to raise the temperature is 1.0kJ.

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