Math, asked by shriya1907, 8 months ago


Determine the digit in the ones place of
the squares of the following numbers.
(1) 324 () 128 (1) 1236 (iv) 3212
pls answer the question ​

Answers

Answered by GK1971
14

Answer:

Hello There,

This is your answer.

Step-by-step explanation:

1) 4 × 4 = 16.

Therefore the digit in the ones place of 324 × 324 = 6.

2) 8 × 8 = 64

Therefore the digit in the ones place of 128 × 128 = 4.

3) 6 × 6 = 36

Therefore the digit in the ones place of 1236 × 1236 = 6

4) 2 × 2 = 4

Therefore the digit in the ones place of 3212 × 3212 = 4.

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Answered by wajidaanjum
0

Answer:

thanks

Step-by-step explanation:

thanks

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