Determine the electric potential at the midpoint of the line joining two charges 2 × 10^5 C
and -1 × 10^5C placed in vacuum 10 cm apart
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Let p be the point of zero potential be p at distance r from the charge 1..
d=16 cm
Electric potential, v=q
1
/4πϵ
o
r+q
2
/4πϵ
o
(d−r)
for v=0,
r
q
1
=−
d−r
q
2
⇒
r
5×10
−8
=
0.16−r
−3×10
−8
r=10 cm
If, point p is outside,
v=q
1
/4πϵ
o
r+q
2
/4πϵ
o
(r−d)
so here, r=40 cm
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