Question

Determine the electrostatic potential energy of a system consisting of two charges 7microC and -2microC (and with no external field) placed at (-9cm, 0,0) and (9cm, 0,0) respectively ​

Answer 1

Answer:

U=14π∈0q1q2r

=9×109×7×(−2)×10−120.18

=−0.7J

The mutual interaction energy of the two charges remains unchanged. In addition, there is the energy of interaction of the two charges with the external electric field. We find,

q1V(r1)+q2V(r2)=AμC0.09m+A−2μC−0.09m

and the net electrostatic energy is

=70−20−0.7=49.3J

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