Question

Determine the empirical formula of a compound containing 47.9% potassium, 5.5% beryllium and 46.6% fluorine by mass. [ At. weight of Be = 9;F = 19;K =39] Work to one decimal place.​

Answer 1

Answer:

K2BeF4

Explanation:

Element  : Potassium

Percentage composition:  47.9    

Atomic weight :   39  

Relative No. of atoms  : 47.9/39 = 1.2

Simplest ratio : 1.2/0.6 = 2

Element  :  Beryllium

Percentage composition:   5.5  

Atomic weight :    9

Relative No. of atoms  :  5.5/9 = 0.6

Simplest ratio : 0.6/0.6 = 1

Element  : Fluorine

Percentage composition:    46.6  

Atomic weight :    19

Relative No. of atoms  :   46.6/19 = 2.4

Simplest ratio : 2.4/0.6 = 4

Hence, empirical formula is: K 2 BeF4 .

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