Question

determine the empirical formula of a compound that contains 60% carbon 32% Oxygen and rest by hydrogen​

Answer 1

Answer:

Empirical formula : C5H8O2

Explanation:

Atomic ratio of :

C=60/12 = 5

O=32/16 = 2

H=8/1 = 8

Least Value = O = 2

Empirical ratio of :

C = 5/2 =2.5

O = 2/2= 1

H = 8/2 = 4

As one value has .5 Multiply e ratio by 2

so we get

Empirical formula = C5 H8 O2

(correct me if I'm wrong)