Determine the empirical formula of acompound containing 47.9% potassium 5.5% beryllium and46.6% flourine by mass
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Dtermine the empirical formula of a compound containing 47.9 % potassium 5.5% beryllium and 46.6% fluorine by mass.
(Atomic weight of Be= 9;F=19;K-39) work to one decimal place.
element % Atomic mas Relative no. of atoms simplest ratio
K 47.9 39 47.9/39 1.2/0.6=2
Be 5.5 9 5.5/9=0.6 0.6/0.6=1
F 46.6 19 46.6/19=2.4 2.4/0.6=4
The empirical formula = K2BeF4.
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Answer:
K 47.9 39 47.9/39 1.2/0.6=2
Be 5.5 9 5.5/9=0.6 0.6/0.6=1
F 46.6 19 46.6/19=2.4 2.4/0.6=4
The empirical formula = K2BeF4.
Explanation:
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