Chemistry, asked by khanadil14, 11 months ago

Determine the empirical formula of acompound containing 47.9% potassium 5.5% beryllium and46.6% flourine by mass​

Answers

Answered by Rajeshkumare
18

Dtermine the empirical formula of a compound containing 47.9 % potassium 5.5% beryllium and 46.6% fluorine by mass.

(Atomic weight of Be= 9;F=19;K-39) work to one decimal place.

element % Atomic mas Relative no. of atoms simplest ratio

K 47.9 39 47.9/39 1.2/0.6=2

Be 5.5 9 5.5/9=0.6 0.6/0.6=1

F 46.6 19 46.6/19=2.4 2.4/0.6=4

The empirical formula = K2BeF4.

Answered by shivanikhosmane73
1

Answer:

K 47.9 39 47.9/39 1.2/0.6=2

Be 5.5 9 5.5/9=0.6 0.6/0.6=1

F 46.6 19 46.6/19=2.4 2.4/0.6=4

The empirical formula = K2BeF4.

Explanation:

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