Determine the empirical formula of an oxide of Iron , which has 69.9% iron and 30.1% dioxygen by mass .
Answers
Answered by
7
1) The molecular mass of H2O =2 ×(Atomic mass of H2) + 1 ×(Atomic mass of O2)
Atomic mass of H2 = 1
Atomic mass of O2 = 16
=(2×1) + 1×16
= 18 g mol–1
ii) The molecular mass of CO2 = 1×(Atomic mass of carbon) + 2 ×(Atomic mass of O2)
tomic mass of carbon = 12
Atomic mass of oxygen =16
= (1×12) + (2×16)
= 12 + 32
= 44g mol–1
iii) Molecular mass of CH4 = 1×(Atomic mass of C) + 4×(Atomic mass of H2)
= (1 ×12) + (4×1)
=12 + 4
= 16g mol-1.
Atomic mass of H2 = 1
Atomic mass of O2 = 16
=(2×1) + 1×16
= 18 g mol–1
ii) The molecular mass of CO2 = 1×(Atomic mass of carbon) + 2 ×(Atomic mass of O2)
tomic mass of carbon = 12
Atomic mass of oxygen =16
= (1×12) + (2×16)
= 12 + 32
= 44g mol–1
iii) Molecular mass of CH4 = 1×(Atomic mass of C) + 4×(Atomic mass of H2)
= (1 ×12) + (4×1)
=12 + 4
= 16g mol-1.
Answered by
1
Answer:
hey mate here is ur ans MARK MY ANSWER AS BRAINLIST OKK BRO AND FOLLOW ME IN BRAINLY BYY .
Attachments:
Similar questions