Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass
Answers
Answer:
Explanation:
the iron oxide has 69.9% iron and 30.1% dioxygen by mass.
Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.
The number of moles of iron present in 100 g of iron oxide are
55.8
69.9
=1.25.
The number of moles of dioxygen present in 100 g of iron oxide are
32
30.1
=0.94.
The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is
1.25
2×0.94
=1.5:1=3:2.
Hence, the formula of the iron oxide is Fe
2
O
3
.
Answer:
The iron oxide has 69.9% iron and 30.1% dioxygen by mass.
Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.
The number of moles of iron present in 100 g of iron oxide are
55.8
69.9
=1.25.
The number of moles of dioxygen present in 100 g of iron oxide are
32
30.1
=0.94.
The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is
1.25
2×0.94
=1.5:1=3:2.
Hence, the formula of the iron oxide is Fe2O3