Chemistry, asked by AttifMukhtar, 9 months ago

Determine the empirical formula of an oxide of iron, which has 69.9% iron and

30.1% dioxygen by mass.​

Answers

Answered by ayushjha187100
0

Explanation:

The iron oxide has 69.9% iron and 30.1% dioxygen by mass.

Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.

The number of moles of iron present in 100 g of iron oxide are

55.8

69.9

=1.25.

The number of moles of dioxygen present in 100 g of iron oxide are

32

30.1

=0.94.

The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is

1.25

2×0.94

=1.5:1=3:2.

Hence, the formula of the iron oxide is F e

2

THE

3

.

hope it will help you...

Answered by sanjaysharma972056
0

Answer:

the empirical formula is :

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