Question

Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass.In this Question isnt we multiply no of molesof oxygen by 2 asit is dioxygen ? plz clear methis quickly. i hope aquick result.

Answer 1

Fe2O3

Relative mole of Fe = % age of Fe by mass / Atomic mass of Fe = 69 . 9 / 56 = 1 . 25

Relative mole of O2 in FeO = % age of O2 by mass / Atomic mass of O2 = 30 . 1 / 16 = 1 . 88

Molar ratio :

1.25 : 1.88

1 : 1.5

2 : 3