Question

determine the empirical formula of an oxide of iron ,which has 69.9% iron and 30.1% diogenes by mass.​

Answer 1

Explanation:

atoms of iron is mass%=69.9%

oxygen is. =30.1%

then, mole=mass%/atomic mass

put the formula

In iron=69.9/57=1.22

in oxygen=30.1%/16=1.89

smallest moles division another moles of oxygen and iron then find moles in whole number of iron is 2and oxygen is 3

then, empherical formula is fe2O3