Question

Determine the empirical formula of an oxide of iron, which has 69.9% iron and 30.1% ​

Answer 1

Explanation:

Let us use general method:

Iron : 69.9% i.e; $\frac{69.9}{53.5}$ = 1.3

Oxygen : 30.1% i.e;$\frac{30.1}{16}$ = 1.8

So, divide by required least number i.e; 1.3 here.

Fe: 1.00     O: 1.38 aprox 1.00

So, formula of oxide is FeO.

Thanking you,

Yours truly,

N. JAYARAMAN

IISc. BENGALURU

HOD, ORGANIC CHEMISTRY.