Question

Determine the empirical formula of the substance having the

following composition : C = 49.3%, H = 9.6%, N = 19.2% and

O = 21.9% ​

Answer 1

Answer:

C₃H₇NO

Explanation:

1) Always assume a 100 percent sample of the given percentages. In this case, you don't need to subtract or find an element because the question already gave it to you.

2) Change the percent symbol to g for grams to convert to moles.

3) After getting each mole, find the smallest decimal and divide that number by the moles of the other elements. Round if necessary.