Determine the emprical formula of a compound with the following composition of mass..
1. C = 48.0%
H = 4.0%
O = 48.0%
2. C = 36.0%
H = 4.0%
N = 28.0%
O = 32.0%
Answers
Empirical and Molecular Formula Questions
These problems may be done with or without a calculator.
1. Determine the empirical formula of a compound with the following composition by mass: 48.0 % C,
4.0 % H and 48.0 % O. [C4H4O3]
2. Determine the empirical formula of a compound with the following composition by mass: 36.0 % C,
4.0 % H, 28.0 % N and 32.0 % O. [C3H4N2O2]
3. Determine the empirical formula of a compound with the following composition by mass: 24.0 % C,
7.0 % H, 38.0 % F and 31.0 % P. [C2H7F2P]
4. Determine the empirical formula of a compound with the following composition by mass: 48.0 % C,
8.0 % H, 28.0 % N and 16.0 % O. [C4H8N2O] If this compound has a molar mass of 200 g, what is its
molecular formula? [C8H16N4O2]
5. A 100 mg sample of a compound containing C, H and O is burned; the combustion resulted in
176 mg of CO2 and 36 mg of H2O. Determine the empirical formula of the compound. [C4H4O3]
6. Determine the empirical formula of a compound with the following composition by mass: 60.0 % C,
12.0 % H and 28.0 % N. [C5H12N2] If this compound has a molar mass of 300 g, what is its molecular
formula? [C15H36N6]
7. Determine the empirical formula of a compound with the following composition by mass: 18.0 % C,
2.5 % H, 63.5% I, and 16.0 % O. [C3H5IO2] If this compound has a molar mass of 400 g, what is its
molecular formula? [C6H10I2O4]
8. Determine the empirical formula of a compound with the following composition by mass: 60.0 % C,
8.0 % H and 32.0 % O. [C5H8O2] If 100 mg of this compound is neutralized with exactly 10.0 mL of
0.0500 M NaOH in a reaction with a 1:1 stoichiometry, what is the molecular formula of
this compound? [C10H16O4]