Question

determine the empricial formula of an oxide of iron which has 69.9% of iron 30.1 % of oxygen by mass​

Answer 1

HERE IS YOUR ANSWER

Answer

Empirical formula of a compound may be defined as the formula which gives the simplest whole number ratio of the atoms of various elements present in one molecule of the compound.

Form the available data Percentage of iron = 69.9

Percentage of oxygen= 30.1 Total percentage of iron & oxygen= 69.9+30.1= 100%

Step 1 calculation of simplest whole number ratios of the elements

Element. _ Fe

Percentage _69.9

Atomic mass _55.84

Atomic ratio _69.9/55.84=1.25

Simplest ratio _1.25= 1

Simplest whole no ratio. _2

Element. _ O

Percentage __30.1

Atomic mass _16

Atomic ratio __30.1/16 = 1.88

Simplest ratio _1.88=1.5

Simplest whole no ratio. _3

Step 2 writing the empirical formula of the compound

The empirical formula of the compound = Fe2 O3

PLZ MARK AS BRILLIANT

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Answer 2

Explanation:

Empirical formula of a compound may be defined as the formula which gives the simplest whole number ratio of the atoms of various elements present in one molecule of the compound.

Form the available data Percentage of iron = 69.9

Percentage of oxygen= 30.1 Total percentage of iron & oxygen= 69.9+30.1= 100%

Step 1 calculation of simplest whole number ratios of the elements

Element

Percentage

Atomic mass

Atomic ratio

Simplest ratio

Simplest whole no ratio

Fe

69.9

55.84

69.9/55.84=1.25

1.25= 1

2

O

30.1

16

30.1/16 = 1.88

1.88=1.5

3

Step 2 writing the empirical formula of the compound

The empirical formula of the compound = Fe2 O3