Question

Determine the energy released in the process $_{1}H^{2}\ +\ _{1}H^{2}\ \longrightarrow\ _{2}He^{4}\ +\ Q$ Given M ($_{1}H^{2}$) = 2.01471 amu M ($_{2}He^{4}$) = 4.00388 amu
(a) 3.79 MeV
(b) 13.79 MeV
(c) 0.79 MeV
(d) 23.79 MeV

Answer 1

I think the answer is B

Answer 2

It is Option B 13.79 Mev...