Determine the energy stored in the surface of a soap bubble of radius 2.1 cm
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Answered by
20
Energy stored in soap bubble = work done to form the bubble.
= 2 x S x A
where S - surface tension of the soap surface
and A - Area of the surface
A = 4π (radius)^2
you know the radius i.e. 2.1 cm = 0.021 m
you must have the value of S.. or any other parameters to find S..
Hope .. it helped ...
= 2 x S x A
where S - surface tension of the soap surface
and A - Area of the surface
A = 4π (radius)^2
you know the radius i.e. 2.1 cm = 0.021 m
you must have the value of S.. or any other parameters to find S..
Hope .. it helped ...
Answered by
46
Radius= 2.1×10^-2 .
Surface tension,T = 4.5 × 10^-2.
No. Of free surfaces in a soap bubble = 2 ( explained in pic).
Area of sphere = 4 pi r^2
Surface energy = T × area × no. of free surfaces.
(4.5 ×10^-2) × [ 4×3.14×(2.1×10^-2)^2] × 2
= 498.50 ×10^-6.
= 4.98 ×10^-4. J
Hope it helped! :D
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