Question

determine the enthalpy of neutralization of N-HCL to acid and N-NaOH strong base by thermochemical method

Answer 1

In Chemical Thermodynamics, it is very interesting to note that the enthalpy of neutralization of one mole of Hydronium ions by equal amount of Hydroxyl ions is always equal to the 57.1 kJ/mole.

Now, HCl is the mono-basic acid, thus it dissociates into H⁺ and Cl⁻. One mole of the H⁺ is formed here.

This one mole of the H⁺ will combines with the one mole of the OH⁻ ions given b y the strong base NaOH.

Therefore, the enthalpy change will be equal to 57.1 kJ.

Now, minus sign will be added before it, since this much amount of the energy will be released when the neutralization will occurs.

Hope it helps.