Question

Determine the equation of the circle passing through points (2;-2); (0:1) and (1; 0)
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Answer 1

Step-by-step explanation:

Let centre of circle be (α,β)

∴(α−1)2+(β−0)2=(α−0)2+(β−1)2

∴α2−2α+1+β2=α2+β2−2β+1

⇒α=β

And

(α−1)2+(β−0)2=(α−1)2+(β+2)2

⇒β2=β2+4β+4

⇒β=−1=α

∴ Radius of circle = (α−1)2+(β−0)2

=(−1−1)2+(−1)2

=5

∴ equation of circle :- (x+1)2+(y+1)2=